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3921. A railway cooperative society lends ₹88365 to a staff member at 6% per annum simple interest for 4 years. Find the simple interest. (SI Set 8)
- A. 21207.6
- B. 21260.6
- C. 20968.6
- D. 26509.5
Answer: 21207.6
Explanation: SI = (P x R x T)/100 = (88365 x 6 x 4)/100 = 21207.6.
3922. A railway equipment supplier offers successive discounts of 25% and 10% on a marked price of ₹5063. Find the final selling price. (SI Set 8)
- A. 3373.53
- B. 3290.95
- C. 3458.53
- D. 3417.53
Answer: 3417.53
Explanation: SP = 5063 x (1-25/100) x (1-10/100) = 5063 x 0.75 x 0.9 = 3417.53.
3923. A marked price of a railway staff uniform kit is ₹3048. A discount of 10% is offered during a department sale. What is the selling price? (SI Set 8)
- A. 2809.2
- B. 2743.2
- C. 2590.8
- D. 2693.2
Answer: 2743.2
Explanation: SP = MP x (1 - 10/100) = 3048 x 0.9 = 2743.2.
3924. A railway canteen vendor bought a stock of items for ₹7184 and sold it at a profit of 30%. Find the selling price. (SI Set 8)
- A. 9373.2
- B. 9247.2
- C. 5028.8
- D. 9339.2
Answer: 9339.2
Explanation: SP = CP x (1 + 30/100) = 7184 x 1.3 = 9339.2.
3925. The monthly ration budget of an RPF barrack was ₹2429. It was increased by 35%. What is the new budget? (SI Set 8)
- A. 3324.15
- B. 3279.15
- C. 3261.15
- D. 1578.85
Answer: 3279.15
Explanation: New value = 2429 x (1 + 35/100) = 3279.15.
3926. In an RPF SI recruitment drive, 2017 candidates appeared for the written exam. If 12% of them qualified for the physical efficiency test, how many candidates qualified? (SI Set 8)
- A. 233.04
- B. 323.04
- C. 271.04
- D. 242.04
Answer: 242.04
Explanation: 12% of 2017 = (12/100) x 2017 = 242.04.
3927. Find the difference between the compound interest and simple interest on ₹12000 for 2 years at 20% per annum (an RPF finance-cell training problem). (SI Set 7)
- A. 529
- B. 960
- C. 480
- D. 433
Answer: 480
Explanation: SI = (12000×20×2)/100 = 4800. CI = 12000[(1+20/100)²-1] = 5280. Difference = 5280 - 4800 = 480. (Shortcut: Diff = P(R/100)² for 2 years.)
3928. A sum of ₹39679 earns simple interest at 5% p.a. for 5 years under Scheme A, versus 11% p.a. for 3 years under Scheme B (an RPF welfare-fund comparison). Find the difference between the two interests. (SI Set 7)
- A. 23013.82
- B. 3263.32
- C. 3174.32
- D. 3087.32
Answer: 3174.32
Explanation: SI(A) = (39679×5×5)/100 = 9919.75. SI(B) = (39679×11×3)/100 = 13094.07. Difference = |9919.75 - 13094.07| = 3174.32.
3929. Three RPF maintenance workers can individually repair a section of boundary fencing in 25, 10, and 11 days respectively. Working together, how many days will they take to finish the job? (SI Set 7)
- A. 3.33
- B. 8.33
- C. 15.33
- D. 4.33
Answer: 4.33
Explanation: Combined rate = 1/25 + 1/10 + 1/11 per day. Time = 1/(1/25+1/10+1/11) = 4.33 days.
3930. Two RPF joggers start at the same point on a circular track of length 400 m and run in opposite directions at 8 m/s and 7 m/s. After how many seconds will they meet for the first time? (SI Set 7)
- A. 34.67
- B. 400
- C. 19.67
- D. 26.67
Answer: 26.67
Explanation: Relative speed (opposite directions) = 8+7 = 15 m/s. Time to meet = Circumference/Relative speed = 400/15 = 26.67 s.
3931. An RPF vehicle travels from post A to post B at 30 km/h and returns the same distance at 60 km/h. Find its average speed for the whole journey. (SI Set 7)
- A. 48
- B. 40
- C. 36
- D. 45
Answer: 40
Explanation: Average speed (equal distances) = 2×S1×S2/(S1+S2) = 2×30×60/(30+60) = 40 km/h.
3932. Find the average of 5 consecutive even numbers starting from 24, used in an RPF fitness-score tally. (SI Set 7)
- A. 10
- B. 90
- C. 57
- D. 28
Answer: 28
Explanation: Consecutive even numbers from 24 to 32. Average = (first+last)/2 = (24+32)/2 = 28.
3933. An RPF SI officer's father's age is currently 4 times the officer's age of 19 years. Find the ratio of father's age to the officer's age after 12 years. (SI Set 7)
- A. 4
- B. 2.84
- C. 2.54
- D. 3.34
Answer: 2.84
Explanation: Father's current age = 4 × 19 = 76. After 12 years: Father = 88, Officer = 31. Ratio = 88/31 = 2.84.
3934. Two RPF canteen contract partners invest ₹16113 and ₹18993 respectively in a joint catering contract for the same period. If the total profit is ₹4774, find the first partner's share. (SI Set 7)
- A. 2582.82
- B. 1578.18
- C. 2191.18
- D. 2600.18
Answer: 2191.18
Explanation: Profit ratio = Capital ratio = 16113:18993. First partner's share = [16113/(16113+18993)] × 4774 = 2191.18.
3935. An RPF canteen mixes two grades of rice costing ₹27/kg and ₹70/kg to get a mixture worth ₹34/kg. Find the ratio in which they must be mixed. (SI Set 7)
- A. 36:7
- B. 36:8
- C. 37:7
- D. 7:36
Answer: 36:7
Explanation: By alligation: ratio = (CP2-Mean):(Mean-CP1) = (70-34):(34-27) = 36:7 = 36:7 (simplified).
3936. A card is drawn at random from a well-shuffled standard deck of 52 playing cards during an RPF aptitude session. What is the probability of drawing a spade? (SI Set 7)
- A. 0.13
- B. 0.39
- C. 0.5
- D. 0.25
Answer: 0.25
Explanation: Favorable outcomes = 13. Total = 52. Probability = 13/52 = 0.25.
3937. From a group of 5 RPF SI candidates, in how many ways can a team (unordered) of 2 be selected? (SI Set 7)
- A. 20
- B. 34
- C. 10
- D. 2
Answer: 10
Explanation: nCr = n!/(r!(n-r)!) = 5!/(2!×3!) = 10.
3938. The bar graph shows the number of RPF SI cases resolved per year: 2021=2440, 2022=1311, 2023=712, 2024=1288, 2025=1820. Find the difference in cases resolved between 2025 and 2024. (SI Set 7)
- A. 515
- B. 543
- C. 532
- D. 554
Answer: 532
Explanation: Difference = |1820 - 1288| = 532.
3939. A pie chart shows the RPF annual budget of ₹5400000 divided among 5 heads by central angle: Equipment=44°, Training=99°, Welfare=107°, Infrastructure=69°, Communication=41°. Find the budget allocated to Welfare. (SI Set 7)
- A. ₹1583408
- B. ₹1605000
- C. ₹1035000
- D. ₹1678495
Answer: ₹1605000
Explanation: Share = (107°/360°) × 5400000 = 1605000.
3940. The table shows RPF SI recruits across 5 zones: North=210, South=316, East=266, West=251, Central=288. What percentage of the total recruits belong to the South zone? (SI Set 7)
- A. 23.74
- B. 44.74
- C. 27.74
- D. 12.74
Answer: 23.74
Explanation: Total = 210+316+266+251+288 = 1331. Percentage for South = (316/1331) × 100 = 23.74%.
3941. An RPF watchtower is 38 m tall. From a point on the ground, the angle of elevation to the top of the tower is 45°. Find the horizontal distance from the point to the base of the tower. (tan 45° = 1) (SI Set 7)
- A. 46
- B. 30
- C. 38
- D. 48
Answer: 38
Explanation: tan(45°) = height/distance => distance = height/tan(45°) = 38/1 = 38 m.
3942. An RPF storage container is a cuboid of dimensions 18 m × 4 m × 12 m. Find its volume. (SI Set 7)
- A. 882
- B. 864
- C. 847
- D. 1010
Answer: 864
Explanation: Volume = l × w × h = 18 × 4 × 12 = 864 cu m.
3943. A circular RPF watchtower base has a radius of 35 m. Find its circumference. (Use π = 22/7) (SI Set 7)
- A. 3850
- B. 178
- C. 220
- D. 265
Answer: 220
Explanation: Circumference = 2πr = 2 × (22/7) × 35 = 220 m.
3944. A rectangular RPF parade ground is 27 m long and 36 m wide. Find its perimeter. (SI Set 7)
- A. 160
- B. 100
- C. 126
- D. 972
Answer: 126
Explanation: Perimeter = 2(length + width) = 2(27+36) = 126 m.
3945. If x² - 7x + 10 = 0 are the roots representing two patrol-team sizes, find the larger root. (SI Set 7)
- A. 7
- B. 2
- C. 3
- D. 5
Answer: 5
Explanation: Factorizing: x² - 7x + 10 = (x - 2)(x - 5) = 0. Roots are 2 and 5. Larger root = 5.
3946. In an RPF duty-roster puzzle, if 5x + 54 = 124, find the value of x. (SI Set 7)
- A. 11
- B. 17
- C. 24.8
- D. 14
Answer: 14
Explanation: 5x = 124 - 54 = 70. x = 70/5 = 14.
3947. Simplify: 6 × (3/6) + 5 = ? (SI Set 7)
- A. 7.5
- B. 11.5
- C. 8
- D. 13
Answer: 8
Explanation: 6 × (3/6) = 3. Adding 5: 3 + 5 = 8.
3948. Simplify: 24 + 12 × 15 − 8 + 18 = ? (SI Set 7)
- A. 224
- B. 550
- C. 214
- D. 204
Answer: 214
Explanation: By BODMAS: 12 × 15 = 180 first. Then 24 + 180 - 8 + 18 = 214.
3949. In an RPF stores ledger, 96173 cartridge boxes need to be arranged into equal rows for a divisor of 7. What is the least number of boxes that must be added to make the total exactly divisible by 7? (SI Set 7)
- A. 2
- B. 8
- C. 5
- D. 0
Answer: 0
Explanation: 96173 mod 7 = 0. Number to add = 7 - 0 = 0 (0 if already divisible).
3950. Find the HCF of the patrol shift durations 46 minutes and 23 minutes used for syncing two RPF post schedules. (SI Set 7)
- A. 29
- B. 18
- C. 23
- D. 46
Answer: 23
Explanation: HCF(46, 23) = 23 (by Euclidean algorithm / prime factorization).
3951. Pipe A can fill a railway water tank in 14 hours and pipe B can fill it in 14 hours. If both pipes are opened together, in how many hours will the tank be filled? (SI Set 7)
- A. 5.5
- B. 11
- C. 14
- D. 7
Answer: 7
Explanation: Combined time = (A x B)/(A+B) = (14 x 14)/(14+14) = 7 hours.
3952. RPF constable A can clear a stretch of railway track of debris alone in 23 days, and constable B can do it alone in 20 days. Working together, in how many days will they finish the job? (SI Set 7)
- A. 9.2
- B. 13.7
- C. 21.5
- D. 10.7
Answer: 10.7
Explanation: Combined time = (A x B)/(A+B) = (23 x 20)/(23+20) = 10.7 days.
3953. A boat used for river patrol by RPF has a speed of 16 km/h in still water. The current speed is 5 km/h. Find the time taken to cover 100 km downstream. (SI Set 7)
- A. 6.25
- B. 4.26
- C. 4.76
- D. 5.76
Answer: 4.76
Explanation: Downstream speed = 16 + 5 = 21 km/h. Time = 100/21 = 4.76 hours.
3954. Two trains of lengths 121 m and 142 m run on parallel tracks in opposite directions at 36 km/h and 45 km/h respectively. Find the time they take to cross each other completely. (SI Set 7)
- A. -105.2
- B. 11.69
- C. 6.69
- D. 17.69
Answer: 11.69
Explanation: Relative speed (opposite dir) = (36+45) x 5/18 = 22.5 m/s. Total length = 121+142 = 263 m. Time = 263/22.5 = 11.69 s.
3955. A railway goods train 308 m long is moving at a speed of 60 km/h. How much time will it take to cross a stationary signal pole? (SI Set 7)
- A. 23.48
- B. 18.48
- C. 16.5
- D. 12.48
Answer: 18.48
Explanation: Speed = 60 x 5/18 = 16.67 m/s. Time = Length/Speed = 308/16.67 = 18.48 seconds.
3956. An RPF patrol vehicle covers a distance of 833 km at a constant speed of 55 km/h. How much time does it take? (SI Set 7)
- A. 16.15
- B. 12.82
- C. 14.15
- D. 15.15
Answer: 15.15
Explanation: Time = Distance/Speed = 833/55 = 15.15 hours.
3957. The average daily patrol distance of 10 RPF beat officers is 83 km. One officer who covered only 47 km is excluded. Find the new average distance of the remaining officers. (SI Set 7)
- A. 86
- B. 87
- C. 88
- D. 83
Answer: 87
Explanation: Total = 10 x 83 = 830. New total = 830 - 47 = 783. New average = 783/9 = 87.
3958. The average age of 9 RPF SI trainees is 48 years. A new trainee aged 45 years joins the batch. Find the new average age. (SI Set 7)
- A. 41.7
- B. 49.7
- C. 47.7
- D. 48
Answer: 47.7
Explanation: Old total = 9 x 48 = 432. New total = 432 + 45 = 477. New average = 477/10 = 47.7.
3959. If 13 railway signal poles cost the same as 5 units cost 12 units of a fourth quantity (13:5 :: 12:x), find x. (SI Set 7)
- A. 9.62
- B. 31.2
- C. 0.62
- D. 4.62
Answer: 4.62
Explanation: 13:5 :: 12:x => x = (5 x 12)/13 = 4.62.
3960. A sum of ₹962 is divided between two RPF constables in the ratio 4:9 as duty allowance. Find the share of the first constable. (SI Set 7)
- A. 296
- B. 666
- C. 272
- D. 318
Answer: 296
Explanation: First share = [4/(4+9)] x 962 = 296.
3961. Find the compound interest on ₹15000 for 2 years at 5% per annum compounded annually, for a railway pension-fund deposit. (SI Set 7)
- A. 1500
- B. 1340.5
- C. 1537.5
- D. 1598.5
Answer: 1537.5
Explanation: A = P(1+R/100)^T = 15000(1+5/100)^2 = 16537.5. CI = A - P = 16537.5 - 15000 = 1537.5.
3962. A railway cooperative society lends ₹76731 to a staff member at 4% per annum simple interest for 3 years. Find the simple interest. (SI Set 7)
- A. 12276.96
- B. 9418.72
- C. 9207.72
- D. 8917.72
Answer: 9207.72
Explanation: SI = (P x R x T)/100 = (76731 x 4 x 3)/100 = 9207.72.
3963. A railway equipment supplier offers successive discounts of 20% and 5% on a marked price of ₹6887. Find the final selling price. (SI Set 7)
- A. 5165.25
- B. 5293.12
- C. 5234.12
- D. 5165.12
Answer: 5234.12
Explanation: SP = 6887 x (1-20/100) x (1-5/100) = 6887 x 0.8 x 0.95 = 5234.12.
3964. A marked price of a railway staff uniform kit is ₹829. A discount of 20% is offered during a department sale. What is the selling price? (SI Set 7)
- A. 712.2
- B. 621.75
- C. 586.2
- D. 663.2
Answer: 663.2
Explanation: SP = MP x (1 - 20/100) = 829 x 0.8 = 663.2.
3965. A railway canteen vendor bought a stock of items for ₹6105 and sold it at a profit of 22%. Find the selling price. (SI Set 7)
- A. 7530.1
- B. 7448.1
- C. 7355.1
- D. 4761.9
Answer: 7448.1
Explanation: SP = CP x (1 + 22/100) = 6105 x 1.22 = 7448.1.
3966. The monthly ration budget of an RPF barrack was ₹4946. It was increased by 22%. What is the new budget? (SI Set 7)
- A. 6010.12
- B. 6094.12
- C. 6034.12
- D. 3857.88
Answer: 6034.12
Explanation: New value = 4946 x (1 + 22/100) = 6034.12.
3967. In an RPF SI recruitment drive, 4225 candidates appeared for the written exam. If 15% of them qualified for the physical efficiency test, how many candidates qualified? (SI Set 7)
- A. 622.75
- B. 712.75
- C. 671.75
- D. 633.75
Answer: 633.75
Explanation: 15% of 4225 = (15/100) x 4225 = 633.75.
3968. Find the difference between the compound interest and simple interest on ₹20000 for 2 years at 5% per annum (an RPF finance-cell training problem). (SI Set 6)
- A. 0
- B. 50
- C. 100
- D. 106
Answer: 50
Explanation: SI = (20000×5×2)/100 = 2000. CI = 20000[(1+5/100)²-1] = 2050. Difference = 2050 - 2000 = 50. (Shortcut: Diff = P(R/100)² for 2 years.)
3969. A sum of ₹19292 earns simple interest at 8% p.a. for 4 years under Scheme A, versus 4% p.a. for 2 years under Scheme B (an RPF welfare-fund comparison). Find the difference between the two interests. (SI Set 6)
- A. 4773.08
- B. 4562.08
- C. 4630.08
- D. 7716.8
Answer: 4630.08
Explanation: SI(A) = (19292×8×4)/100 = 6173.44. SI(B) = (19292×4×2)/100 = 1543.36. Difference = |6173.44 - 1543.36| = 4630.08.
3970. Three RPF maintenance workers can individually repair a section of boundary fencing in 21, 11, and 11 days respectively. Working together, how many days will they take to finish the job? (SI Set 6)
- A. 2.86
- B. 14.33
- C. 4.36
- D. 8.36
Answer: 4.36
Explanation: Combined rate = 1/21 + 1/11 + 1/11 per day. Time = 1/(1/21+1/11+1/11) = 4.36 days.
3971. Two RPF joggers start at the same point on a circular track of length 300 m and run in opposite directions at 10 m/s and 3 m/s. After how many seconds will they meet for the first time? (SI Set 6)
- A. 23.08
- B. 9.08
- C. 42.86
- D. 41.08
Answer: 23.08
Explanation: Relative speed (opposite directions) = 10+3 = 13 m/s. Time to meet = Circumference/Relative speed = 300/13 = 23.08 s.
3972. An RPF vehicle travels from post A to post B at 50 km/h and returns the same distance at 80 km/h. Find its average speed for the whole journey. (SI Set 6)
- A. 66.54
- B. 57.54
- C. 61.54
- D. 65
Answer: 61.54
Explanation: Average speed (equal distances) = 2×S1×S2/(S1+S2) = 2×50×80/(50+80) = 61.54 km/h.
3973. An RPF control room logs incident serial numbers from 1 to 37 in a single shift. Find the sum of all serial numbers. (SI Set 6)
- A. 746
- B. 743
- C. 703
- D. 687
Answer: 703
Explanation: Sum = n(n+1)/2 = 37(37+1)/2 = 703.
3974. An RPF SI officer's father's age is currently 6 times the officer's age of 12 years. Find the ratio of father's age to the officer's age after 5 years. (SI Set 6)
- A. 4.53
- B. 4.23
- C. 5.03
- D. 6
Answer: 4.53
Explanation: Father's current age = 6 × 12 = 72. After 5 years: Father = 77, Officer = 17. Ratio = 77/17 = 4.53.
3975. Two RPF canteen contract partners invest ₹11979 and ₹16397 respectively in a joint catering contract for the same period. If the total profit is ₹11863, find the first partner's share. (SI Set 6)
- A. 6855
- B. 5371
- C. 5008
- D. 4572
Answer: 5008
Explanation: Profit ratio = Capital ratio = 11979:16397. First partner's share = [11979/(11979+16397)] × 11863 = 5008.
3976. An RPF canteen mixes two grades of rice costing ₹32/kg and ₹72/kg to get a mixture worth ₹65/kg. Find the ratio in which they must be mixed. (SI Set 6)
- A. 7:33
- B. 33:7
- C. 8:33
- D. 7:34
Answer: 7:33
Explanation: By alligation: ratio = (CP2-Mean):(Mean-CP1) = (72-65):(65-32) = 7:33 = 7:33 (simplified).
3977. A card is drawn at random from a well-shuffled standard deck of 52 playing cards during an RPF aptitude session. What is the probability of drawing a spade? (SI Set 6)
- A. 0.45
- B. 0.51
- C. 0.25
- D. 0.1
Answer: 0.25
Explanation: Favorable outcomes = 13. Total = 52. Probability = 13/52 = 0.25.
3978. From a group of 7 RPF SI candidates, in how many ways can a team (unordered) of 3 be selected? (SI Set 6)
- A. 35
- B. 210
- C. 42
- D. 14
Answer: 35
Explanation: nCr = n!/(r!(n-r)!) = 7!/(3!×4!) = 35.
3979. The bar graph shows the number of RPF SI cases resolved per year: 2021=827, 2022=901, 2023=1972, 2024=699, 2025=1269. Find the difference in cases resolved between 2022 and 2023. (SI Set 6)
- A. 1053
- B. 1083
- C. 1111
- D. 1071
Answer: 1071
Explanation: Difference = |901 - 1972| = 1071.
3980. A pie chart shows the RPF annual budget of ₹1800000 divided among 5 heads by central angle: Equipment=53°, Training=47°, Welfare=92°, Infrastructure=46°, Communication=122°. Find the budget allocated to Training. (SI Set 6)
- A. ₹235000
- B. ₹265874
- C. ₹211825
- D. ₹460000
Answer: ₹235000
Explanation: Share = (47°/360°) × 1800000 = 235000.
3981. The table shows RPF SI recruits across 5 zones: North=86, South=269, East=229, West=265, Central=152. Find the average number of recruits per zone. (SI Set 6)
- A. 200.2
- B. 228.2
- C. 195.2
- D. 212.2
Answer: 200.2
Explanation: Total = 1001. Average = 1001/5 = 200.2.
3982. An RPF watchtower is 48 m tall. From a point on the ground, the angle of elevation to the top of the tower is 45°. Find the horizontal distance from the point to the base of the tower. (tan 45° = 1) (SI Set 6)
- A. 40
- B. 38
- C. 48
- D. 58
Answer: 48
Explanation: tan(45°) = height/distance => distance = height/tan(45°) = 48/1 = 48 m.
3983. An RPF storage container is a cuboid of dimensions 19 m × 11 m × 5 m. Find its volume. (SI Set 6)
- A. 1045
- B. 996
- C. 1102
- D. 1183
Answer: 1045
Explanation: Volume = l × w × h = 19 × 11 × 5 = 1045 cu m.
3984. A circular RPF watchtower base has a radius of 7 m. Find its area. (Use π = 22/7) (SI Set 6)
- A. 154
- B. 205
- C. 134
- D. 44
Answer: 154
Explanation: Area = πr² = (22/7) × 7 × 7 = 154 sq m.
3985. A rectangular RPF parade ground is 38 m long and 7 m wide. Find its perimeter. (SI Set 6)
- A. 266
- B. 95
- C. 90
- D. 81
Answer: 90
Explanation: Perimeter = 2(length + width) = 2(38+7) = 90 m.
3986. If x² - 19x + 88 = 0 are the roots representing two patrol-team sizes, find the larger root. (SI Set 6)
- A. 13
- B. 8
- C. 11
- D. 6
Answer: 11
Explanation: Factorizing: x² - 19x + 88 = (x - 11)(x - 8) = 0. Roots are 11 and 8. Larger root = 11.
3987. In an RPF duty-roster puzzle, if 3x + 50 = 74, find the value of x. (SI Set 6)
- A. 3
- B. 8
- C. 12
- D. 24.67
Answer: 8
Explanation: 3x = 74 - 50 = 24. x = 24/3 = 8.
3988. Simplify: 10 × (3/6) + 4 = ? (SI Set 6)
- A. 12
- B. 14.5
- C. 8
- D. 9
Answer: 9
Explanation: 10 × (3/6) = 5. Adding 4: 5 + 4 = 9.
3989. Simplify: 36 + 8 × 4 − 9 + 16 = ? (SI Set 6)
- A. 71
- B. 82
- C. 183
- D. 75
Answer: 75
Explanation: By BODMAS: 8 × 4 = 32 first. Then 36 + 32 - 9 + 16 = 75.
3990. In an RPF stores ledger, 29390 cartridge boxes need to be arranged into equal rows for a divisor of 13. What is the least number of boxes that must be added to make the total exactly divisible by 13? (SI Set 6)
- A. 3
- B. 10
- C. 2
- D. 4
Answer: 3
Explanation: 29390 mod 13 = 10. Number to add = 13 - 10 = 3 (0 if already divisible).
3991. Find the LCM of the patrol shift durations 57 minutes and 55 minutes used for syncing two RPF post schedules. (SI Set 6)
- A. 3141
- B. 1
- C. 3135
- D. 3130
Answer: 3135
Explanation: LCM(57, 55) = (57 x 55)/HCF(57,55) = (57 x 55)/1 = 3135.
3992. Pipe A can fill a railway water tank in 14 hours and pipe B can fill it in 6 hours. If both pipes are opened together, in how many hours will the tank be filled? (SI Set 6)
- A. 4.2
- B. 10
- C. 3.7
- D. 5.2
Answer: 4.2
Explanation: Combined time = (A x B)/(A+B) = (14 x 6)/(14+6) = 4.2 hours.
3993. RPF constable A can clear a stretch of railway track of debris alone in 8 days, and constable B can do it alone in 21 days. Working together, in how many days will they finish the job? (SI Set 6)
- A. 8.79
- B. 3.79
- C. 5.79
- D. 14.5
Answer: 5.79
Explanation: Combined time = (A x B)/(A+B) = (8 x 21)/(8+21) = 5.79 days.
3994. A boat used for river patrol by RPF has a speed of 16 km/h in still water. The current speed is 3 km/h. Find the time taken to cover 74 km downstream. (SI Set 6)
- A. 4.63
- B. 3.89
- C. 3.39
- D. 4.89
Answer: 3.89
Explanation: Downstream speed = 16 + 3 = 19 km/h. Time = 74/19 = 3.89 hours.
3995. Two trains of lengths 132 m and 109 m run on parallel tracks in opposite directions at 54 km/h and 18 km/h respectively. Find the time they take to cross each other completely. (SI Set 6)
- A. 12.05
- B. 6.05
- C. 16.05
- D. 24.1
Answer: 12.05
Explanation: Relative speed (opposite dir) = (54+18) x 5/18 = 20 m/s. Total length = 132+109 = 241 m. Time = 241/20 = 12.05 s.
3996. A railway goods train 185 m long is moving at a speed of 60 km/h. How much time will it take to cross a stationary signal pole? (SI Set 6)
- A. 11.1
- B. 3.1
- C. 14.1
- D. 9.91
Answer: 11.1
Explanation: Speed = 60 x 5/18 = 16.67 m/s. Time = Length/Speed = 185/16.67 = 11.1 seconds.
3997. An RPF patrol vehicle covers a distance of 885 km at a constant speed of 90 km/h. How much time does it take? (SI Set 6)
- A. 8.85
- B. 9.83
- C. 8.83
- D. 10.83
Answer: 9.83
Explanation: Time = Distance/Speed = 885/90 = 9.83 hours.
3998. The average daily patrol distance of 7 RPF beat officers is 73 km. One officer who covered only 63 km is excluded. Find the new average distance of the remaining officers. (SI Set 6)
- A. 75.67
- B. 74.67
- C. 69.67
- D. 73
Answer: 74.67
Explanation: Total = 7 x 73 = 511. New total = 511 - 63 = 448. New average = 448/6 = 74.67.
3999. The average age of 11 RPF SI trainees is 80 years. A new trainee aged 120 years joins the batch. Find the new average age. (SI Set 6)
- A. 87.33
- B. 80
- C. 81.33
- D. 83.33
Answer: 83.33
Explanation: Old total = 11 x 80 = 880. New total = 880 + 120 = 1000. New average = 1000/12 = 83.33.
4000. If 9 railway signal poles cost the same as 5 units cost 5 units of a fourth quantity (9:5 :: 5:x), find x. (SI Set 6)
- A. 0.5
- B. 9.78
- C. 2.78
- D. 9
Answer: 2.78
Explanation: 9:5 :: 5:x => x = (5 x 5)/9 = 2.78.
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